Question

How many milliliters of an aqueous solution of 0.137 M calcium chloride is needed to obtain 18.1 grams of the salt? mL

Answer 1

Molarity ds cacl = 0-137 M Mass d cac 18-1 9Y ds cac mol Molan masS Volume Molasi ty o Mass o cacl, volume Molas mars t cac cac 137 volume volume = 1190.24m :Molasity o 232 M 2 mass d Al CN Molan mass d Al C)213 m volume 125m Allwg) Mass Malani ty d 1000 volume m) Al L) Molan mass o Mass dAlCN) LO00 232 25 213 6-177 9Y lcwo Mass ot A

P6 4 Pe P mala mass F124 31mol Pel, Mola mass z 137.3 lmel From equatt um A mole P, Pso duce 4moles Pel Cix 1242 9 P, Poduce x137-3)3 Pc3 124 9Y PL proouce 547. 2 r Pe $-66 x s49.2)y Pel 5-66 9Y 4 $ 3 Produce 124 2S068 8Y Theonetical re ld d Pe actual te ld 74reld Theo se tical Yie ld 81 372 20-4 X100 25-068