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How many milliliters of an aqueous solution of 0.182 M calcium acetate is needed to obtain...

How many milliliters of an aqueous solution of 0.182 M calcium acetate is needed to obtain 9.15 grams of the salt?

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Answer #1

Ans :

Number of moles of salt = given mass / molar mass

= 9.15 / 158.17

= 0.058 moles

Moles = Molarity x volume in Liters

0.058 = 0.182 x V

V = 0.3178 L

or 317.8 mL

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