How many milliliters of an aqueous solution of
0.182 M copper(II) sulfate is
needed to obtain 10.3 grams of the salt?
number of moles of copper sulfate = mass of copper sulfate / molar mass of copper sulfate
number of moles of copper sulfate = 10.3 g / 159.609 g.mol^- = 0.0645 mole
molarity = number of moles of solute / volume of solution in L
0.182 = 0.0645 / volume of solution in L
volume of solution in L = 0.354 L
1L = 1000 mL
0.354 L = 354.0 mL
Therefore, the volume of solution is 354.0 mL
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