Calculate the pH after adding 10.00 mL of 0.15 M HCl to 50 mL of pure water.
use dilution formula
M1*V1 = M2*V2
1---> is for stock solution
2---> is for diluted solution
Given:
M1 = 0.15 M
V1 = 10 mL
V2 = 50 mL + 10 mL = 60 mL
use:
M1*V1 = M2*V2
M2 = (M1*V1)/V2
M2 = (0.15*10)/60
M2 = 0.025 M
This is concentration of HCl
So,
[H+] =0.025 M
use:
pH = -log [H+]
= -log (2.5*10^-2)
= 1.6021
Answer: 1.60
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