Question

Compound Z spectra IR (as a KBr disc) 3083 3055 3020 1596

Answer 1

Hi Dear you missed an important peak also, which is due to amide N-H stretch in the region 3100 - 3500 cm-1, may be your amide nitrogen is disubstituted in that case we won't observe N-H stretch.

You haven't given a single clue about compound, such as aromatic, amine, amide, alkene - so it is very difficult to predict without these input - I'm gonna try my best for you! If still you have any queries feel free to ask me at comment section below.

Spectra analysis: IR (5 marks) Wavelength v (cm-1) Strength a Type of vibration/functional group 3083 medium sp2 =C-H stretch 3055 medium sp2 =C-H stretch 3020 medium sp2 =C-H stretch 1651 strong amide C=0 stretch 1596 strong amide N-H bending Indicate if s (strong), m (medium). W (weak) indicate whether stretching or bending and the functional group it refers to

Hope this helped you!

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