Question

1. Consider the balanced equation for the following reaction: 302(g) + 2CH3OH() → 2CO2(g) + 4H2O(1) If 3.77 moles of O2 reacts with 2.66 moles of CH3OH, determine how much excess reactant remains in the reaction 1.33 moles 2.00 moles 0.15 moles 1.40 moles 2.66 moles Use the slider to rate your confidence on this question. 100 Not at all confident Very confident

Answer 1

Balanced chemical equation is:

3 O2 + 2 CH3OH ---> 2 CO2 + 4 H2O

3 mol of O2 reacts with 2 mol of CH3OH

for 3.77 mol of O2, 2.513 mol of CH3OH is required

But we have 2.66 mol of CH3OH

so, O2 is limiting reagent

According to balanced equation

mol of CH3OH reacted = (2/3)* moles of O2

= (2/3)*3.77

= 2.513 mol

mol of CH3OH remaining = mol initially present - mol reacted

mol of CH3OH remaining = 2.66 - 2.513

mol of CH3OH remaining = 0.15 mol

Answer: 0.15 moles