From the balanced equation we can say that
5 mole of O2 requires 2 mole of CH3CHO so
95.2 mole of O2 will require
= 95.2 mole of O2 *(2 mole of CH3CHO / 5 mole of O2)
= 38.1 mole of CH3CHO
But we have 33.9 mole of CH3CHO which is in short so CH3CHO is limiting reactant
From the balanced equation we can say that
2 mole of CH3CHO produces 4 mole of H2O so
33.9 mole of CH3CHO will produce
= 33.9 mole of CH3CHO *(4 mole of H2O / 2 mole of CH3CHO)
= 67.8 mole of H2O
Therefore, the number of moles of H2O produced would be 67.8
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