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Time Remaining:03:33:52 1. Consider the following balanced equation: 502(g) + 2CH3CHO(1) -> 4CO2(g) + 4H2O(1) 11 95.2 moles o
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Answer #1

From the balanced equation we can say that

5 mole of O2 requires 2 mole of CH3CHO so

95.2 mole of O2 will require

= 95.2 mole of O2 *(2 mole of CH3CHO / 5 mole of O2)

= 38.1 mole of CH3CHO

But we have 33.9 mole of CH3CHO which is in short so CH3CHO is limiting reactant

From the balanced equation we can say that

2 mole of CH3CHO produces 4 mole of H2O so

33.9 mole of CH3CHO will produce

= 33.9 mole of CH3CHO *(4 mole of H2O / 2 mole of CH3CHO)

= 67.8 mole of H2O

Therefore, the number of moles of H2O produced would be 67.8

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Time Remaining:03:33:52 1. Consider the following balanced equation: 502(g) + 2CH3CHO(1) -> 4CO2(g) + 4H2O(1) 11...
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