1. Consider the balanced equation for the following reaction: 6HC(aq) + 2Al(s)-3H2(g)+ 2AICI3 (s) If the...
Time Remaining:04:12:6 Consider the following balanced equation: 6HCl(aq) + 2Al(s) + 3H2(g) + 2AlCl3(S) 11 1.80x102 grams of HCl(aq) reacts with an excess of Al(s), and the percent yield is 53.6%, how many grams AlCl3(s) will actually be produced? 2.76x109 3.54x1099 9.88x1099 1.18*109 5.02*1099 Use the slider to rate your confidence on this question 100 Not at all confident Very confident
Consider the following balanced equation: 6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s) If 17.3 moles of HCl(aq) and 7.07 moles of Al(s) are allowed to react, and the percent yield is 71.8%, how many moles of AlCl3(s) will actually be produced?
Thankyou! Consider the following balanced equation for the following reaction: 3H2SO4(aq) + 2Fe(s) + 3H2(g) + Fe2(SO4)3(aq) Determine the amount of H2(9) formed in the reaction if the percent yield of H2(g) is 65.0% and the theoretical yield of H2(g) is 39.0 grams. ООООО 15.2 grams 30.5 grams 25.4 grams 60.0 grams 43.2 grams N Consider the balanced equation for the following reaction: 2Na3PO4(aq) + 3Ca(NO3)2(aq) - NaNO3(aq) + Ca3(PO4)2(8) If the percent yield of NaNO3(aq) is 90.0% and 0.877...
Consider the balanced equation for the following reaction: 3H2SO4(aq) + 2Fe(s) → 3H2(g) + Fe2(SO4)3(aq) If 57.0 grams of Fe(s) reacts with an excess of H2SO4(aq) and the percent yield of H2(g) is 73.0%, determine the mass of H2(g) formed in the reaction.
Time Remaining:03:55:13 1. Consider the following balanced equation: 3CuO(s)+ 2NH3(g)3H2O()+3Cu(s) + N2(g) If 80.9 moles of CuO(s) and 31.4 moles of NH3(g) are allowed to react, and the percent yield is 90.9%, how many moles of Cu(s) will actually be produced? 62.4 moles 56.7 moles 40.5 moles 42.8 moles 80.0 moles Use the slider to rate your confidence on this question. -1 100 Not at all confident Very confident Irc 55 44 R save subit Rut 101
Consider the following unbalanced equation: H2SO4(aq)+Fe(s)H2(g) + Fe2(SO4)3(aq) If 17.6 moles of H2SO4 ( aq) and 10.2 moles of Fe(s) are allowed to react, what is the theoretical yield of H2(g) in moles? 21.0 moles 88.4 moles 81.7 moles 15.3 moles 12.3 moles Use the slider to rate your confidence on this question. 100 Not at all confident Very confident submt save
Thankyou! Consider the following balanced equation: 502(g) + C3H8(9) 3CO2(g) + 4H20(1) If 19.9 moles of O2(g) and 4.42 moles of CzHg(g) are allowed to react, what is the theoretical yield of CO2(g) in moles? 0 O OOOO 41.0 moles 94.3 moles 36.3 moles 35.3 moles 11.9 moles Consider the balanced equation for the following reaction: 6HCl(aq) + 2Al(s) + 3H2(g) + 2AlCl3(s) How much excess reactant remains in the reaction if 54.1 grams of HCl reacts with 85.8 grams...
Time Remaining:03:23 1. Consider the balanced equation for the following reaction: 3Fe2O3(s) + CO(g) + CO2(g) + 2Fe3O4(s) How much excess reactant remains in the reaction if 46.8 grams of Fe2O3 reacts with 22.4 grams of CO? 0.195 moles 0.702 moles 0.800 moles 0.267 moles 0.507 moles Use the slider to rate your confidence on this question 100 Not at all confident Very confident
2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g) What is the limiting reactant, theoretical and percent yield of this equation? 1.03 grams of Al foil 35.10 grams of KOH 15 grams of Sulfuric acid 20 grams of water the mass of the product is 24.88 grams
When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2Al(s)+6HCl(aq)⟶2AlCl3(aq)+3H2(g)2Al(s)+6HCl(aq)⟶2AlCl3(aq)+3H2(g) What volume of H2(g)H2(g) is produced when 3.30 g of Al(s) reacts at STP?