Question

Consider the following unbalanced equation: H2SO4(aq)+Fe(s)H2(g) + Fe2(SO4)3(aq) If 17.6 moles of H2SO4 ( aq) and 10.2 moles of Fe(s) are allowed to react, what is the theoretical yield of H2(g) in moles? 21.0 moles 88.4 moles 81.7 moles 15.3 moles 12.3 moles Use the slider to rate your confidence on this question. 100 Not at all confident Very confident submt save

Answer 1

The balanced equation is

3 H₂SO₄ + 2 Fe -----> 3 H₂ + Fe₂(SO₄)₃

From the balanced equation we can say that

3 mole of H2SO4 requires 2 mole of Fe so

17.6 mole of H2SO4 will require

= 17.6 mole of H2SO4 *(2 mole of Fe / 3 mole of H2SO4)

= 11.7 mole of Fe

But we have 10.2 mole of Fe which is in short so Fe is limiting reactant

From the balanced equation we can say that

2 mole of Fe produces 3 mole of H2 so

10.2 mole of Fe will produce

= 10.2 mole of Fe *(3 mole of H2 / 2 mole of Fe)

= 15.3 mole of H2

Therefore, the number of moles of H2 produced would be 15.3