Calculate the de Broglie wavelength (in picometers) of a hydrogen atom traveling at 435 m/s. Express your answer us...

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Question

Answer 1

Answer #1

The de-Broglie wavelength is given by $\lambda$ = h/mv

$\lambda$ = 6.625*10^-34/1.627*10^-27*435

= 0.00936*10^-7 m = 936*10^-12 m

The de- Broglie wavelength of hydrogen atom with a velocity of 435m/sec is 936 pm

Answer 2

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