An aqueous solution is 0.467 M in HCl. What is the molality of the solution if the density is 1.23 g/mL? Show work please.
Answers are a) 0.374 m b) 0.115 m c) 0.268 m d) 0.574 m
0.467 moles in 1 L of solution = 0.467 M
Mass of 1 L ( 1000 mL) = 1230 g
mass of HCl = 0.467 mol x 36.461 g/mol = 17.02 g
mass water = 1230 - 17.02 =1212.9 g = 1.2129 Kg
molality = 0.467 mol/ 1.2129 = 0.385 .... option a is correct
An aqueous solution is 0.467 M in HCl. What is the molality of the solution if the density is 1.23 g/mL? Show work plea...
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