Question

A toy rocket is launched from rest at an angle of 43 degrees and follows a straight line path as long as the engine is burning. The engine burns for 9.4 seconds with an acceleration of 5.2 m/s^2. Once the engine turns off, the rocket is considered a projectile. How far from the launch point does the rocket land.

Use the Kinematic Equations to solve the problem

X_f=X_i+Vix(t)+1/2a_xt²

V_fx=V_ix+a_xt

V_fx²=V_ix²+2a_x (X_f -X_i)

Answer 1

2 iVt t at 1x +a t Vi 2 + 2a 43 given Now S2 m32 t 9.4s a at 48 g& ms V at nous 2 Vix t (1x-f) 9.4 5. 2 cn430). any le ot launch 4 3 (X 168 02 m 156.68 m 168-02X tam 4 3

3 48.88 ms This is peak pont at pomt B V. AB V Sen 430) 48.88 S 43 9-8 3.4 t A B 2. AB AB total heisht L95+89951 pun o waup g t 2|3 38 m

to dascend this heisht ver hcal directin the epuatin Can We now atply for 2- BC Ys-Y 213 38 2.13-38- BC BC= 6.6 total time tAC la A to LAR RC= 3 4+6 6 = horigontal veloc: From A to C remain same 4-8 88 35 7mi1 C43 1 AR 3 S.75 x 10 357. Sm. total distance omLaunch 357. S 168. 02+ 525. 5 2 m