Question

Hello can anyone help solve this please in Python the way it's asked?

Question 22 40 pts List Comprehensions Write the solution to a file named p2.py and upload it here. Comprehensions will show up at the midterm exam, so it's important to practice. a) Write a list comprehension that returns a list [0, 1,4, 9, 16, .. 625] starting from range(0, 26). (lots of list elements were omitted in ...) b) Write a list comprehension that returns the list ["1**2=1", "2 2-4", "3* * 2-9", . "25*2-625"1. (lots of list elements were omitted in.) c) Write a list comprehension that returns all tuples (a b,c) with a b,c integers, such that 1-b<c<a<-100 and 2 = b2+c2 Consider a list of strings, like this: ['one', 'seven', 'three', 'two', 'ten']. Write a list comprehension that produces a list with tuples where the first element of the tuple is the length of an element in the initial list, the second element of the tuple is the element of the initial list capitalized, and the resulting list contains only tuples for strings with the length longer than three characters. For our example above the list comprehension should return [(5, 'SEVEN'), (5, 'THREE')]. e) Consider a list of full names formatted "Firstname Lastname", like ["Jules Verne", "Alexandre Dumas", "Maurice Druon"]. Write a list comprehension that produces a list with the full names n the format Lastname, Firstname". The resulting list should look like ['Vemne, Jules', Dumas, Alexandre', Druon, Maurice'] for ... in [ The simplest solution may involve a nested comprehension: [ for in Write a function called unzip that takes as parameter a sequence (list or tuple) called seq of tuples with two elements. The function must return a tuple where the first element is a list with the first members of the sea tuple and the second element is a list with the second members of the seq tuple. This example clarifies what is required: 1st (1, "one"), (2, "two"), (3, "three")] tup unzip(1st) rints ((1, 2, 31, r'one, 'two', 'three ']) Write a function called oncatenate that takes as parameter a separator (a string) and an arbitrary numbe of additional arguments, all strings, and that returns the concatenation of all given strings using the given separator. Example: concatenate(:, "one", "two", "three") returns "one: two: three" and concatenate( and *, "Bonny", "Clyde") returns "Bonny and Clyde" For a single string we have: concatenate(* and *, "single") return "single"

Answer 1

a)

print([i*i for i in range(0,26)])

print(i*i for i in range(0, 26) ] ) [0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625]

b)

print([str(i)+"**2="+str(i**2) for i in range(0,26)])

print(str(i)+" **2="+str(i**2) for i in range(0,26)]) ['0**2-0', 1**2=1', '2**2-4', '3**2=9', '4**2=16', '5**2=25', '6**2=36', '7**2=49', '8**2=64', '9**2=81', 121', 12**2-144', '13**2=169 *2=441', 22**2=484', '23**2=529', '24**2=576', '25**2-625'] '10**2-100', '11**2= '14**2=196', '15**2-225', '16**2=256', '17**2=289', '18**2=324', '19**2=361', '20**2-400', '21*

c)

print([(a,b,c) for a in range(1,100+1) for b in range(1,100+1) for c in range(1,100+1)  if a*a==b*b+c*c ])

print ([(а,b,с) for a in range (1,100+1) for b in range(1,100+1) for c in range(1,100+1) if a*as-b*b+с*c ]) (5, 3, 4), 5, 4, 3), (10, 6, 8), (10, 8, 6), (13, 5, 12), (13, 12, 5), (15, 9, 12), (15, 12, 9), (17, 8, 15), (17, 15, 8), (2 0, 12, 16), (20, 16, 12), (25, 7, 24), (25, 15, 20), (25, 20, 15), (25, 24, 7), (26, 10, 24), (26, 24, 10), (29, 20, 21), (29, 21, 20), (з0, 18, 24), (зө, 24, 18), (34, 16, 30), (34, з0, 16), (35, 21, 28), (35, 28, 21), (37, 12, 35), (37, 35, 12), (39, 1 5, 36), (39, 36, 15), (40, 24, 32), (40, 32, 24), (41, 9, 40), (41, 40, 9), (45, 27, 36), (45, 36, 27), (50, 14, 48), (50, 30, 40), (50, 40, з0), (50, 48, 14), (51, 24, 45), (51, 45, 24), (52, 20, 48), (52, 48, 20), (53, 28, 45), (53, 45, 28), (55, 33, 4 4), (55, 44, 3), (58, 4о, 42), (58, 42, 40), (60, 36, 48), (60, 48, 36), (61, 11, 60), (61, 60, 11), (65, 16, б3), (65, 25, 6 0), (65, 33, 56), (65, 39, 52), (65, 52, 39), (65, 56, 33), (65, 60, 25), (65, 63, 16), (68, 32, 60), (68, 60, 32), (70, 42, 5 6), (70, 56, 42), (73, 48, 55), (73, 55, 48), (74, 24, 70), (74, 70, 24), (75, 21, 72), (75, 45, 60), (75, 60, 45), (75, 72, 2 1), (78, 30, 72), (78, 72, 30), (80, 48, 64), (80, 64, 48), (82, 18, 80), (82, 80, 18), (85, 13, 84), (85, 36, 77), (85, 40, 7 5), (85, 51, 68), (85, 68, 51), (85, 75, 40), (85, 77, 36), (85, 84, 13), (87, 60, 63), (87, 63, 60), (89, 39, 80), (89, 80, 3 9), (90, 54, 72), (90, 72, 54), (91, 35, 84), (91, 84, 35), (95, 57, 76), (95, 76, 57), (97, 65, 72), (97, 72, 65), (10е, 28, 9 6), (100, 60, 80), (100, 80, 60), (100, 96, 28)]

d)

lst = ['one','seven','three','two','ten']
print([(len(i),i.upper()) for i in lst])

1st ['one','seven','three','two','ten'] print([(len(i),i.upper()) for i in lst]) (3, 'ONE') (5, 'SEVEN'), (5, 'THREE'), (3, 'Two'), (3, 'TEN')]

e)

names = ["Jules Verne","Alexandre Dumas","Morris Druon"]
print([n.split()[1]+","+n.split()[0] for n in names ])

f)

def unzip(seq):
    first,second = [],[]
    for t in seq:
        first.append(t[0])
        second.append(t[1])
    return tuple([first,second])

lst = [(1,"one"),(2,"two"),(3,"three")]
print(unzip(lst))

def unzip(seq): first, second for t in seq: first.append(t[0]) second.append (t [1] ) return tuple([first,second]) 1st = [(1,"one"), (2,"two"), (3,"three")] print(unzip(1st)) ([1, 2, 31, 'one', 'two', 'three')

g)

def concatenate(sep,*arg):#*arg is used to take arbirary number of arguments as list
    if len(arg)==1:
        return arg[0]
    else:
        s = arg[0]
        for i in range(1,len(arg)):
            s+=sep+arg[i]
    return s


print(concatenate(':',"one","two","three"))
print(concatenate(' and ',"Bonny","Clyde"))
print(concatenate('and',"single"))

def concatenate (sep, *arg) :#*arg is used to take arbirary number of arguments as list if len(arg)==1: return arg[0] else: arg[0] for i in range(1,len(arg)): st=sep+arg[i] S= return s print (concatenate (':',"one","two","three")) print (concatenate (' and ',"Bonny","Clyde " ) ) print(concatenate('and',"single")) one: two:three Bonny and Clyde single

h)

lst = list(range(0,20))
print(lst[16:10:-1])

list(range (0,20)) print (1st[16:10:-1]) 1st [16, 15, 14, 13, 12, 11]

i)

lst = list(range(0,20))
print(lst[16:10:-2])

list(range (0,20)) print (1st[16:10:-2]) 1st [16, 14, 12]