Question

W See Periodic Table D See Hint The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (HOOCCOOH) and must be removed before the stems are used to make rhubarb pie. If pka1 = 1.23 and pka2 = 4.19, what is the pH of a 0.0228 M solution of oxalic acid?

Answer 1

Dear student,

Answer! acid (H₂ GO4). since rhubarb plant contain diprotic so il have two value of ka, : pkai = -logka, -log kay = 1.23 kas = 10-01-23 10-2 = 5.88 x ": Рka - - log va, kar = 4.19 kar = 10-4.19 = 16-98 10-05-19 = 6.45 X 100 Now, HOy (aq) + H+ (aq) kan H₂ GO4 (as) 0.0228 Buitial 0.0228-4 04 (aq) + 4 + (aq), kar HC OY - Initial a final dry

• Again Cucour4+7 kai = [HC204] [47] [H₂ C Oy 2 of 5 5.88 X10-2 – 2*M 0.0228-1 5.88x1020.0228-x) = 42 212 + 5.88X10-? 1.34064*10 =0 n = -0.076 S s he is neglected as cone Ma is neglected as H2 = 0.017 I can't be negatine 3 17x103. Now, Kar = [ Goy] [ Hit] [He C₂ oy] 6.454105 = 4x4 & 6.45*105 (ory) = y2 9² + 6.45x10 y 6.45x105x0.017 20 y² + 6.45x10 sy 1.0965810620 y = - 1.079x103 sy, es neglected as cone. Y 2 = 1.01 2103 I can't be negative 178 10 3+101x103 [ht] = x+y = = 18.01 X10

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