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* Show all work for trial lon the next page Trial 1 Trial 2 Trial 3 Trial 4 Volume NaOH used T 12.63 mL 11.30m 1 12.65 me Mol
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Answer #1

You haven't gave the Strength of the NaOH solution, it is required for all the Calculations in your question. I've assumed the NaOH Concentration to be X(M) and done All the calculations, you just replace X by the NaOH concentration, while doing the Final Calculations. I'm also assuming that the Volume of "6 Down" Soda, taken for Titration, is 10mL, it is also required to calculate the Molarity of Citric Acid, but not given in your question.

Trial 11:3x mmol Trial 3 . 1265x mal Concentration of NaOH = x (M) Trial of Doo Moles of NaOH added & 1263x mmd Moles of Citr

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