Can I please get full working and explanations for each step for this past exam question. Both parts (a) and (b) and (c). Thanks will up-vote
(a)
(b)
kobs. = k1 + k-1 = 5.2×10-3 s-1
Half life of first order reaction ,t1/2 =( ln2) /kobs. = 0.693/(5.2×10-3) s = 133.298 s
= 133.3 s
(c)
(k_1 + k1 )×t = ln(xe/(xe-x))
For nearly completion reaction, k1 >>>k-1
k1 + k-1 = k1 and xe = [cis]0 and xe -x = [cis]
k1 t = ln([cis]0/[cis])
The concentration of cis-isomer decreases exponentially.
[cis]t = [cis]0e-k1t
Can I please get full working and explanations for each step for this past exam question. Both parts (a) and (b) and (c)...
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