Question

Question 26 Calculate the output power Pout (RL) for the unloaded Common Emitter Amplifier below BDC=200, BAC = 150, re 0.39 Vs- 538 mVpp, Vcc 15 V, R1=1 KQ, R2 = 330 2 RC= 1000, RE1= 8.20, RE2= 36 0, RL 0.19 KO Enter your results in mW. SR1 RL Vcc C1 Vin Beta Vs R2 RE1 RE2 C2 ww

Answer 1

Andyi's AC Vcc=ov 2 Ci and C Shost Crcui e-ov) SRIEO AKn REK Nout Pac I50 RE22 s=538 R-3302 Re 36n TIt ITHT Vout RE 8.N 019kn R=330S2S 2 REL RFIKA 538mv PP TT TILT TH

model ie Keplace tronsistor by its oc ic -Ttic i6teib -+Pa)s E Given Ye 0139-N Vout B REI ) +ex RE) Jere Vs= xPac)x +(+Paci Re RE

VoutexR Pacibx R Vout from and Voltage Gah Av Vout PacxRL Av= Vout VS -PocxRL 1+Pac)RE Bac= RL O.19k De O 39n 8.3-2 Av= Vout Vs ISOX O (9 x1000 I+150)x (6.374 + 8.2

=21.972 Vout -20992 x Vs haue Ve S5 we 38 m Vp-p 3 -1.972 X 538 x10 V Vout l1.821 V p-P Vout Vout (EP) 2 2 Oubpeut Powes 821 2 O 19x10 -3 1,467 10 O19 91.93 mW 7 output pouen