Question

i need help on #1 c and d

A degreasing agent, tetrachloroethylene, is produced in the reaction CH (g) + 4 HCl(g) +20 (g) → C Cl.(l) + 4H2O(1) rk/mol): 52.26 -9231 0 a) determine AH"for CCl4(1) AHºrn = - 878.5 kJ - 285.8 a) AHⓇ for CC.(I) = -52.28 kJ b) How much heat (kJ) would be eve amounts of HCl and O:)? much heat (kJ) would be evolved when 7.5 kg of C2H4(g) reacts completely (with stoichiometric b) heat, qp=-2.35 x 10'ki c) Using the equation for work done bylon the system; w= .PAV, calculate the amount of work done on by the system in part b), if the reaction runs at 500 K, and with a constant pressure of 3.5 atm. c) work - 2,2x103 d) Determine the change in internal energy, AE, for the reaction in b). d) AE = -2.33x109 kJ

Answer 1

6 Imole (28.059) of C₂H4 gives -878.5 KJ heat Imole 28.058 7.5 kg = 7500 g = 7500 g 1 1 = 267.3797 moles heat released by 267.3797 moles = 267.3797X-878.5 kJ =-2.35X10

c) number of moles of sty = 267.4 moles number of moles of Hl = 4x 267. 4 - 1069. 6 mol moles of = 2x 267.4 = 53418 total moles = 1871.8 moles PV =HRT V = nRT K.no 1871.8 76 x 0.0821 kobox 5ook 3.5 affn - 21,953.54 L L initial volume

- final = 21,953.54L L initial volume As in reaction only liquids are formed, final volume becomes 'o' AV = find Vinitial = -21,953.54L = PAV=-3.5 atm x -21.95.54 L = 76837.39 L-ahm. = 7785.55 KJ .. W dy q=w+AE = AE = Q-W. = 2 2.35x10 – 778555 = -2.43x 10 kJ <H4 5