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17. [1pt) A wheel of mass m = 1.87 kg and moment of inertia, I = 1.530 kg.m- is supported by a pivot a distance d=0.17 m from

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i) Since the majority of the angular momentum, is due to the spin about the axle the direction of the angular momentum is along the direction of the angular velocity about that axle which is along the x-axis hence the answer is C

ii) The direction of torque of gravity about the pivot point is given by right hand thumb rule, which is along y-axis hence the answer is E

iii) Say, the axle rotates with angular velocity w, the rate of change of angular momentum which is given by cross product of w and L should be along the direction of the torque of gravity. Therefore w will be along Z-axis, hence the axle will spin about Z-axis in counter-clockwise sense as seen from above.

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