Richardson Extrapolation is mainly a simple method for boosting the accuracy of certain numerical procedures. This one does the elimination of errors. Though it can only remove errors of the form:
Derivation of the General Form of Richardson Extrapolation
This part will show how the error is being removed through Richardson Extrapolation.
Assumptions:
Derivation Proper:
Romberg Integration
Now that we have established the pre-requisites, let’s go to the main thing.
Romberg Integration
Romberg intergation combines the Composite Trapezoidal Rule with Richardson Extrapolation.
Below is the overview of the integration process:
this is exactly what we are doing
This tells us that we need to compute where the two arrows are from to compute where the two arrows are pointing at. The most accurate estimate of the integral is always the last diagonal term of the array. This process is continued until the difference between two successive diagonal terms becomes sufficiently small.
The overview above can be summarized into the formula:
5. Let f a, b R be a 4 times continuously differentiable function. For n even, consider < tn = b, a to < t< an...
5. [4 bonus points) Let F be a continuously differentiable non-decreasing function on R with F' = f. Show that 1,6)dF(a) = 5,5(x)}(a)dx 2 A A for every non-negative function g on R and a Borel set A.
Please prove by setting up the theorem below (Chain Rule) v:RR is continuously differentiable. Define the Suppose that the function function g : R2R by 8(s, t)(s2t, s) for (s, t in R2. Find ag/as(s, t) and ag/at(s, t) Theorem 15.34 The Chain Rule Let O be an open subset of R and suppose that the mapping F:OR is continuously differentiable. Suppose also thatU is an open subset of Rm and that the functiong:u-R is continuously differentiable. Finally, suppose that...
4. Let F be a continuously differentiable function, and let s be a fixed point of F (a) Prove if F,(s)| < 1, then there exists α > 0 such that fixed point iterations will o E [s - a, s+a]. converge tO s whenever x (b) Prove if IF'(s)| > 1, then given fixed point iterations xn satisfying rnメs for all n, xn will not converge to s.
-5) Assume that f : [a, b] → R is a continuously differentiable function on [a, b] with f(a) = f(6) = 0 and x dx = 1. Prove: (2) f'(x) dx = -1/2, and [cm)? ds. [ f(a)dx > 1/4
Question 1 (Quadrature) [50 pts I. Recall the formula for a (composite) trapezoidal rule T, (u) for 1 = u(a)dr which requires n function evaluations at equidistant quadrature points and where the first and the last quadrature points coincide with the integration bounds a and b, respectively. 10pts 2. For a given v(r) with r E [0,1] do a variable transformation g() af + β such that g(-1)-0 and g(1)-1. Use this to transform the integral に1, u(z)dz to an...
5. Let f : R -R be a differentiable function, and suppose that there is a constant A < 1 such that If,(t)| < A for all real t. Let xo E R, and define a sequence fan] by 2Znt31(za),n=0,1,2 Prove that the sequence {xn) is convergent, and that its limit is the unique fixed point of f. 5. Let f : R -R be a differentiable function, and suppose that there is a constant A
Let γ(t) be a differentiable curve in R". If there is some differentiable function F : Rn R with F(γ(t)) C constant, show that DF(γ(t))T is orthogonal to the tangent vector γ(t).
this is numerical analysis please do a and b 3. Consider the trapezoidal rule (T) and Simpson's rule (S) for approximating the integral of a relatively smooth function f on an interval (a, b), for which the following error local estimates are known to hold: (6 - a)"}" (n), for some 7 € (a, b), 12 [ f(z)de –T(S) = [ f(a)der – 5(8) = f(), for some 5 € (a, b), where 8 = (b -a)/2. (a) Given a...
Let a continuously differentiable function f: Rn → R and a point x E Rn be given. For d E Rn we define Prove the following statements: (i) If f is convex and gd has a local minimum at t-0 for every d E R", then x is a minimiser of f. (ii) In general, the statement in (i) does not hold without assuming f to be convex. Hint: For) consider the function f: R2-»R given by Let a continuously...
Consider the function Let where f(t) is differentiable for all t ∈ R. Show that z satisfies the partial differential equation (x2 − y2 ) ∂z/∂x + xy ∂z/∂y = xyz for all (x, y) ∈ R2 \ { (t, 0)|t ∈ R }.