Question

w is equal to 14 rad/s. i have tried every way of solving this problem but i cannot seem to get it, could someone explain please.

Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Two small disks A and B of mass 3 kg and 1.5 kg, respectively, may slide on a horizontal, frictionless surface. They are connected by a cord 600 mm long and spin counterclockwise about their mass center G at the rate of 14 rad/s. At t O, the coordinates of G are Xo = O and yo = 2 m, and its velocity is vo = (1.2 m/s)i +(0.96 m/s)j. Shortly thereafter, the cord breaks; disk A is then observed to move along a path parallel to the y axis and disk Balong a path which intersects the x axis at a distance b=7.5 m from O. Determine the velocities of A and Bafter the cord breaks. (You must provide an answer before moving on to the next part.) After the cord breaks, the velocity of A is 5.677 After the cord breaks, the velocity of B is 8.20 m/st m/s 66.9

Answer 1

Date Iwhal londions A. mv AC AG+CB BG me Matmn O.6m AB m 9-0S -0-2m 4.5 Ba D-4m Linear mamentm m(4.)ai +0- - 5ti +422j Angulat momentun About (Ha) GA Xm, +GBxmg to-2(3)(02 mx 4d) 91 a Ctratixm0)-1)() (Ha), (5.04 Mm/s) Abord 0 Usig teas fermula FmTs (Ho)e7xm +CHa)o 23 (S4+4.82+ro l0-8+5.04-S76)

Ki nahe enegyhg bela fomda Tom t 2 m: + 2 De 2. 2. + 2 23-52) 40-5933 (S.3136 + 11-76 + Ca) Lansewm lneat momeuhm Lo L S4i+4323MAm o t7mx 3(v, ) +S + equadng cethemts q 3 : Equahg Ceethients 4.32 3 1 (Va)y vs)y 288 2VA Consevaton eneray To T Tm 40-593 +) 2 2

Subotung aud 405131V0-72-6+0-7(283-2 40-593-1 -72+62 202+3 2-4V 4.SY-8-64-24652 0 2 Va -ト92-5-478 =0 Vh- 2-489 m/s and ()3-6m/s = 2-88 2(3-48) S/w 860.カーニニ Vs 3-6-4.0 9j V 5.454 m/s S60.7/ Fax mngk an 9) = 48-70 3.6

After the cord breaks, the velocity of A is V_A = 3.489 m/s

After the cord breaks, the velocity of B is V_B = 5.454 m/s

angle $\small \alpha$ = 48.70^o