slider P Y-75 mls 125 mm 65 mm A. 40mm slider P Y-75 mls 125 mm 65 mm A. 40mm
Describe how you would make up a 60 mls of 125 mM solution of CaCl2 formula weight: CaCl2 2H2O = 147 Please show all steps
3 (75 mm) -3" 75" (175 mm) (125 mm) 150 mm 75 mm (100 mm) 1100 mm) -22" (ww 095) - 16" wwood) - 18- (450 mm) -12 - (300 mm) 4 #8 4 x 25 mm) 5# 8 (5 x 25 mm) -12" (300mm (50 mm) 2" (50 mm) (b) 12" (300 mm) 3.9 Determine the design moment strength of the sections shown in Fig. 3.41. Neglect the lack of symmetry in (b). Given: f = 4 ksi (30...
14. A solid shaft 65 mm dia. Is subjected to a torque of 75 MN-m. find the maximum stress induced in the shaft 15. a solid shaft is to transmit a torque of 11 x 105 N-mm. find the minimum diameter of shaft, if shearing stress is not to exceed 75 MPa.
Calculate the centroid and moment of inertia of the following figure with respect to the y axis with respect to the x axis. 225 mm 225 mm 50 mm 400 mm 75 mm 75 mm 100 mm 300 mm 225 mm 225 mm 50 mm 400 mm 75 mm 75 mm 100 mm 300 mm
A subject has normal values of 125/80 mm Hg blood pressure and heart rate of 65 bpm and a cardiac output of 5 L min-1. C. If the heart rate does not change, what is the new peripheral resistance?
1. For the inverted slider crank shown below, (a) Differentiate the velocity equations to get the acceleration equations and put into matrix form (b) Solve for and θ3 (c) Setup and differentiate the position equations to get the velocity of point B (d) Finally, solve for the acceleration magnitude and direction of point B 62 where a2-75 mm, a3-400 mm, d-125 mm, r-193.6 mm, θ2-150°, θ3-11.170 and θ-60ad/sec (constant). The position equations are as follows: a2 sin θ-r sin θ3-0...
Determine the x and y coordinates of the centroid of the shaded area. 225 mm 75 mm Som 150 mm
The slider P can be moved inward by means of the string S, while the slotted arm rotates about point O. The angular position of the arm is given by θ = 0.80t - 0.044t2, where θ is in radians and t is in seconds. The slider is at r = 1.47 m when t = 0 and thereafter is drawn inward at the constant rate of 0.13 m/s. Determine the velocity v and acceleration a of the slider when...
Figure 5.2 shown a hollow brass pipe with 125 mm diameter and 6 mm thickness (c) has an axial load P applied 5 mm from the geometric axis Using Young Modulus, E 120 GPa, determine; . The load P for which the horizontal deflection at the mid-point C is 5 mm ii. The corresponding maximum stress in the column. P A 125 mm 2.7 m C B Figure 5.2 Brass pipe Figure 5.2 shown a hollow brass pipe with 125...
(1allow = (ta)allow = 80 MPa 65 MPa 35 mm 2.36x10 mm 75 GPa Shaft properties 60 mm 20.36 x 10 mm 25 GPa 2300 mm 3500 m (kN-m A composite torsion member consists of two solid shafts joined at flange B. Shafts (1) and (2) are attached to rigid supports at A and c, respectively. (MPa) Ital (MPa) Using the allowable shear stresses indicated on the sketch, determine the maximum torque T that may be applied to flange B...