Question

​​​​​​​Please solve and explain steps thanks

A sample of 200 ROM computer chips was selected on each of 30 consecutive days, and the number of nonconforming chips on each day was as follows: The data has been given so that it can be copied into R as a vecto. #### non.conforming = c(11, 21, 27, 16, 35, 17, 4, 22, 9, 22, 30, 18, 15, 21, 20, 19, 12, 23, 11, 22, 15, 16, 12, 26, 28, 14, 11, 17, 12, 26) #Construct a chart by using the following code. You will need to enter your values for pbar, LCL and UCL pbar JPad LCL= UCL= plot(non.conforming/200, ylim = c(0,.5)) abline(h pbar, Ity 2) abline(h LCL, Ity 3) abline(h UCL, Ity 3) Construct a p chart and examine it for any out-of-control points. (Round your answers to four decimal places.) LCL UCL= 0.25 0.25 0.20 0.20 UCL UCL 0.15 0.15 0.10 0.10 0.05 LCL 0.05 F LCL 0.00 Day 5 10 15 20 25 30 LI Day -0.05 15 25 30 10 20 0.00 p p 0.25 0.25 0.20 0.20 UCL 0.15 0.15 UCL 0.10 0.10 0.05F LCL 0.05 LCL Day 0.00 15 30 10 20 25 0.00 15 10 20 25 30 Comment on the chart. The value of s on the 5th day lies below the LCL, so an out-of-control signal is generated The value of s on the 5th day lies above the UCL, so an out-of-control signal is generated. All points are between these limits, so the process appears to be out of control Most points are between these limits, so the process appears to be in control with respect to variability. All points are between these limits, so the process appears to be in control

Answer 1

Results:

P-bar = CL= 0.092

LCL= 0.03068834

UCL= 0.1533117

since

R-code:

Terminal x Console non. conforming=c(11,21,27 ,16,35,17,4,22,9,22,30,18,15,21,20,19,12,23, 11,22,15,16,12,26,28,14,11,17,12,26) n-200 size=rep (n, 30) k-length(size) pi-non. conforming/size pbar sum(pi)/k qbar-1-pbar st. err-sqrt(pbar*qbar/n) # Control limits of Pbar chart CL=pbar > LCL -pbar - 3*st.err UCL =pbar 3*st.err cat ("P chart: CL=",CL, "LCL=", LCL, "UCL=", UCL,"\n") P chart CL 0.092 LCL= 0.03068834 UCL= 0.1533117 plot (non. conforming/200,main="P bar chart",xlab-"sample Numbers",ylim=cC0,0. 25)) abline (h-pbar,1ty=2) abline(h-LCL, 1ty 3) abline(h-uCL,lty-3)

P bar chart 10 15 25 Sample Numbers non.conforming/200 00 0 0.05 0.10 0.15 0.20 0.25 LO 20 30

Correct Graph : Option (A)

Correct answer: Option (B) The value of Sbar on the 5th day lies above the UCL, so an out-of -control is generated