Question

A solid acid has an equivalent mass of 92.0 g/equiv. What mass of this acid would require just 34.5 mL of 0.216 N NaOH for titration?

2. A solid acid has an equivalent mass of 92.0 g/equiv. What mass of this acid would require just 0.216 N NaOH for titration?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given, volume d Naote domality o.216N do. s eavalent mola * volenele) Nomality O216 x 1 7. 452 me 7.us2xIO ivalent velume 10

Add a comment
Know the answer?
Add Answer to:
A solid acid has an equivalent mass of 92.0 g/equiv. What mass of this acid would require just 34.5 mL of 0.216 N NaOH f...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 0.900 g sample of phthalic acid re- quired 40.0 mL of NaOH solution for complete...

    A 0.900 g sample of phthalic acid re- quired 40.0 mL of NaOH solution for complete titration. What weight ofben- zoic acid would require 25.0 mL of the same NaOH solution for the titration? In the formula for benzoic acid shown to the right, the acidic hydrogen is circled . Complete and balance the following acid-base reactions:

  • 2. A 0.2349 g sample of an unknown acid requires 33.66 mL of 0.1086 M NaOH...

    2. A 0.2349 g sample of an unknown acid requires 33.66 mL of 0.1086 M NaOH for neutralization to a phenolphthalein end point. There are 0.42 mL of 0.1049 M HCI used for back-titration. a. How many moles of OH- are used? moles OH moles H b. How many moles of H+ from HCI? moles H c. How many moles of H+ are there ins solid acid? (Eq. 5) g/mol d. What is the molar mass of the unknown acid?...

  • 3. A 0.7026 g sample of an unknown acid requires 40.96 mL of 0.1158 M NaOH...

    3. A 0.7026 g sample of an unknown acid requires 40.96 mL of 0.1158 M NaOH for neutralization to a phenolphthalein end point. There are 1.22 mL of 0.1036 M HCl used for back-titration. a. How many moles of OH are used? How many moles of Ht from HCI? moles OH moles H+ b. How many moles of Ht are there in the solid acid? (Use Eq. 5.) moles H+ in solid c. What is the molar mass of the...

  • The titration of 0.9541g of KHP (molar mass=204.227 g/mol)requires 42.18 mL of NaOH solution. What is...

    The titration of 0.9541g of KHP (molar mass=204.227 g/mol)requires 42.18 mL of NaOH solution. What is the concentration of the NaOH solution?

  • As part of Lab 11 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH an...

    As part of Lab 11 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH and dissolve it into 100.0 mL of water. You then measure 0.1993 g of KHP (204.22 g/mol) and place it in a clean, dry 100-mL beaker, and then dissolve the KHP in about 25 mL of water and add a couple of drops of phenolphthalein indicator. You titrate this with your NaOH(aq) solution and find that the...

  • Acid-base titration questions. Please help! Thanks. 2. Given that 20.00 mL of phosphoric acid solution required...

    Acid-base titration questions. Please help! Thanks. 2. Given that 20.00 mL of phosphoric acid solution required 15.50 mL of 0.200M NaOH for the first equivalent point. What is the molarity of the phosphoric acid? 3. A student titrated 25.00 mL of cola and it required 18.27 mL of 0.0100 M NaOH to reach the 1'equivalence point. Calculate the molar concentration of phosphoric acid in this brand of cola. 4. If the density of the "Cola" drink is 1.00 g/mL. What...

  • Suppose 1.00 g of NaOH is used to prepare 250 mL of an NaOH solution. Compare...

    Suppose 1.00 g of NaOH is used to prepare 250 mL of an NaOH solution. Compare the expected molarity of this solution to the actual average molarity you measured in the standardization. What do you notice? Do you think the results would have been more accurate if a different type of acid or base were used in the standardization? Why, or why not? There are many different primary standards that could be used in a standardization titration. What are the...

  • 7. + -19 points My Notes A 2.256-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 35.0...

    7. + -19 points My Notes A 2.256-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 35.0 mL of this solution was titrated with 0.08152-M NaOH. The pH after the addition of 25.80 mL of base was 6.74, and the equivalence point was reached with the addition of 48.31 mL of base. a) How many millimoles of acid are in the original solid sample? Hint: Don't forget the dilution. mmol acid b) What...

  • 35.25 mL of NaOH solution are required to titrate 0.5745 g of an unknown monoprotic acid....

    35.25 mL of NaOH solution are required to titrate 0.5745 g of an unknown monoprotic acid. Prior standardization of the NaOH determined its concentration as 0.1039 M. 1. Use the data provided to determine the molar mass of the unknown acid 2. If 20 mL of a 1.0 M solution of the unknown monoprotic acid is placed into a beaker and 10 mL of 0.1 M NaOH is added, the pH of the final solution is 1.9. What is the...

  • 3) A weak monoprotic acid has a pKa 6.15. 50.00 mL of an 0.1250M aqueous solution...

    3) A weak monoprotic acid has a pKa 6.15. 50.00 mL of an 0.1250M aqueous solution of this weak acid is titrated with 0.1000M NaOH. a) What is the equivalence point volume and 2 equivalence point volume for this titration? Find the pH b) before the titration begins; c) after 20.00 mL of the NAOH has been added, d) after 62.50 mL of the NaOH has been added; and e) after 85.00 mL of the NAOH has been added. 4)...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT