Question

10) Determine the size of two stage trickling filter using the NRC equations. Assume both filters have the same efficiency BO

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Answer #1

Step 1:

yin=195 mg/l

yeff=20 mg/l

Assuming that the removal efficiency is 30%

yin=136.5 (195x0.7=136.5)

E=yin-yeff/yin

E=136.5-20/136.5=0.85

Step 2:

Assume E1=0.75

E=E1+E2(1-E1)

0.85=0.75+E2(0.3)

E2=0.33

Step 3:

E=100/(1+0.4432(W/VF)0.5)

W=3785x195x0.7=516.652kg/day

75=100/(1+0.4432(516.652/Vx1.8)0.5)

V=524m3

Depth=2m

Area=524/2=262m2

0.785d2=262

d=18.2m, provide 18.5m diameter filter

Step 4:

For the second stage using the same NRC equation

W2=W1x0.25(because 75% of the efficiency is acheived in 1st stage only)

W2=129.163

E2=100/(1+0.4432/(1-E1)(W2/VF)0.5)

33=100/(1+0.4432/0.25)(129.163/Vx1.8)0.5

V=54m3

0.785d2=54

d=8.29m, provide 8.5m diameter filter

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