Step 1:
yin=195 mg/l
yeff=20 mg/l
Assuming that the removal efficiency is 30%
yin=136.5 (195x0.7=136.5)
E=yin-yeff/yin
E=136.5-20/136.5=0.85
Step 2:
Assume E1=0.75
E=E1+E2(1-E1)
0.85=0.75+E2(0.3)
E2=0.33
Step 3:
E=100/(1+0.4432(W/VF)0.5)
W=3785x195x0.7=516.652kg/day
75=100/(1+0.4432(516.652/Vx1.8)0.5)
V=524m3
Depth=2m
Area=524/2=262m2
0.785d2=262
d=18.2m, provide 18.5m diameter filter
Step 4:
For the second stage using the same NRC equation
W2=W1x0.25(because 75% of the efficiency is acheived in 1st stage only)
W2=129.163
E2=100/(1+0.4432/(1-E1)(W2/VF)0.5)
33=100/(1+0.4432/0.25)(129.163/Vx1.8)0.5
V=54m3
0.785d2=54
d=8.29m, provide 8.5m diameter filter
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