Question

A manufacturer of dustless chalk instituted a quality control program to monitor chalk density. The sample standard deviations of densities for 24 different subgroups, each consisting of n 8 chalk specimens, were as follows into R with the name k.sdevs. This data has been coded so that you may copy and paste .sdevs c(0.204, 0.317, 0.096, 0.184, 0.233, 0.214, 0.324, 0.287, 0.148, 0.209, 0.053, 0.147, 0.273, 0.348, 0.158, 0.213, 0.390 0.184, 0.150, 0.226, 0.274, 0.121, 0.094, 0.058) mean(k.sdevs) Construct your own Control Chart. 0.15 ##### change this value to be the same as your calculated LCL UCL 0.35 ##### change this value to be the same as your calculated UCL plot(k.sdevs) LCL ablineth ean(k.sdevs)) abline(h UCL, Ity 2) .. Calculate limits for an S chart. (Round your answers to four decimal places.) s= 0.2044 an LCL = 0.1491 UCL 0.2597

Answer 1

Solution Given data 148 0. O. o213 0.348, o-15?, 0.213, 0.390, o184, 0.80, o053 0-2a 0-274 ,o.121, o.094 )0.058 0.150 Calcutate Noa to Σs K C 4.905 4 to find Noa tene n8 Thee e an o.965 Noc to find the Ne knoa hat The famula LCL is give of 3s an

ezuation No ae have to Substitute (2 and a Values In. then Ge get 3 X0ol-o.765) 0204ly 0.965 x 0-2044V- o.9312 Lre 0Rell 0.965 3 X 0044 Vc 0.068 8 LL o165 3 x 0.204l(0.2623) = 0.2o4l LcL 0.965 o.0536 3 X LcL 0.2o44 O.165 3 xo.0555 O.1665 0-2ol 0.037 Lc L O.039 LCL= Now to tind the ucL We knoa that given Te famuta of - an UcL 0.965) 0.965

0ol4 -0.1 312 -0.204 + 3 X UCL o.965 0.20 3 0o4 4 Vao688 o.965 UCL 0.965 UCL 0.965 UCL C UcL 0.3769 o.3101 UcL