We wish to determine by a comparison test vwhether or not the improper integral below is convergent. If it is convergen...
We wish to determine by a comparison test whether or not the improper integral below is convergent. If it is convergent, we would like in addition to provide Question 2 an upper bound for its value. daz 1 point I= /25g5+91/2 Choose the correct reasoning 1/2 The integral is convergent since 25591/2> such that 0< for all: < 1 ,hence dr =4/9 1/4 1 1 and I 3z1/4 25z5 91/2 The integral is divergent since 25 9r 34 for all...
We want to use the comparison test to determine whether (x + 2x 2/5 is convergent. Choose the correct argument. 0 1 ve for all < >1 and 42 The integral is convergent since — (x + 2x)2/5 22/5 0 2/5 /5-1 <0. 2 opent since a 125215 5 to for all z 2 1 and ſº 215 dz = 215–1 <0. his dvorantino e 23275 2 trail 2 2 1 um fio adig do = -0. 1 The integral...
Determine if the improper integral is convergent or divergent, and calculate its value if it is convergent. 9x e 8xdx Calculate the value of the improper integral. Select the correct choice below and fill in any answer boxes within your choice. се 9xe 8xdx(Type an integer or a fraction. Simplifty your answer.) 0 O B. The integral diverges. Determine if the improper integral is convergent or divergent, and calculate its value if it is convergent. 9x e 8xdx Calculate the...
1. Use the Comparison Test to determine whether the integral is convergent or divergent. 2. Determine whether the integral conveges or diverges. Evaluate the integral in the case that it is convergent rinfinity 2/23 - 1dx 2 cln(2x)d.2
Use the Integral Test to determine whether the series is convergent or divergent. ∞ n n2 + 8 n = 1 Evaluate the following integral. ∞ 1 x x2 + 8 dx Since the integral finite, the series is . Use the Integral Test to determine whether the series is convergent or divergent. n2 8 Evaluate the following integral. OO dx Since the integral ---Select--- finite, the series is ---Select---
Determine whether the integral is convergent or divergent. integral_-infinty^0 1/3 - 4x dx convergent divergent If it is convergent, evaluate it. (If the quantity diverges, enter diverges.) Determine whether the integral is convergent or divergent. integral_8^infinity 1/x^2 + x dx convergent divergent If it is convergent, evaluate it. (If the quantity diverges, enter diverges.) Determine whether the integral is convergent or divergent. integral_-2^14 5/4 squareroot x + 2 dx convergent divergent If it is convergent, evaluate it. (If the quantity...
(1 point) We will determine whether the series n3 + 2n an - is convergent or divergent using the Limit Comparison Test (note that the Comparison Test is difficult to apply in this case). The given series has positive terms, which is a requirement for applying the Limit Comparison Test. First we must find an appropriate series bn for comparison (this series must also have positive terms). The most reasonable choice is ba - (choose something of the form 1/mp...
7) Use the Ordinary Comparison Test to determine whether the series is convergent or divergent. Υ n (a) (6) Σ η η 5" 3η – 4 M8 M8 (Inn) 2 (c) η (d) tan n2 n3 η-2 1 (e) Σ (6) Σ 2n + 3 2n + 3 ή-1 1-1
To test the series e 2n for convergence, you can use the Integral Test. (This is also a geometric series, so we could n=1 also investigate convergence using other methods.) Find the value of e-24 dx = Preview Ji What does this value tell you about the convergence of the series e-2n? the series definitely diverges the series might converge or diverge: we need more information the series definitely converges Compute the value of the following improper integral, if it...
(1 pt) Test each of the following series for convergence by either the Comparison Test or the Limit Comparison Test. If either test can be applied to the series, enter CONV if it converges or DIV If it diverges. If neither test can be applied to the series, enter NA. (Note: this means that even if you know a given series converges by some other test, but the comparison tests cannot be applied to it, then you must enter NA...