Ka = 1.51*10^-5
pKa = - log (Ka)
= - log(1.51*10^-5)
= 4.821
use:
pH = pKa + log {[conjugate base]/[acid]}
6.63 = 4.821+log {[C4H7O2-]/[HC4H7O2]}
log {[C4H7O2-]/[HC4H7O2]} = 1.809
[C4H7O2-]/[HC4H7O2] = 64.41
Answer: 64.4
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