Question

answer neatly and correctly please!

The university data center has two main computers. The center wants to examine whether computer 1 is receiving tasks that require processing times comparable to those of computer 2. A random sample of 12 processing times from computer 1 showed a mean of 62 seconds with a standard deviation of 17 seconds, while a random sample of 9 processing times from computer 2 (chosen independently of those for computer 1) showed a mean of 66 seconds with a standard deviation of 15 seconds. Assume that the populations of processing times are normally distributed for each of the two computers and that the variances are equal. Construct a 99% confidence interval for the difference uyu, between the mean processing time of computer 1, 11, and the mean processing time of computer 2, U. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your responses to at least two decimal places. What is the lower limit of the 99% confidence interval? What is the upper limit of the 99% confidence interval? x 6 ?

Answer 1

The statistic software output for this problem is:

Two sample T summary confidence interval: Hi : Mean of Population 1 2: Mean of Population 2 H1 - H2 : Difference between two means (with pooled variances) 99% confidence interval results: Difference Sample Diff. Std. Err. DF L. Limit U. Limit Vi - 2 -4 7.1382546 19-24.42208 16.42208

The 99% confidence interval is :

Lower limit = -24.42

Upper limit = 16.42