Question

Part 6B (selchion of soluent) A.mixhwe B: Pare Otue 3 pres +3 aflg es ove Beaner Is mt) t Ccu Hexme Purt -Jiserea is 1o Cn 15 ant m a A Here ohras cH,clr Aceme strat REA =5150 ReAe 6.9- 893eA= 0. o 7.9 Skatnet 7.76 RfA 5 =0.334 EB6.9 o810 7.75 7.Y Sahote CHycle as solve for Pat C Date Witness/TA

lab report include discussion and conclusion

Answer 1

Diswssion RE Value hfth is Ratio al distonu wavelled Travelled by 50lvent Salute to dis tanl Retaxdation of uanity amount a ample in a Phase Ratatve to Mobile Phase 5olurt Reamains in starionay RF Value = uo Phase means Mear is mmobile and Phase] Rf valu ne5ouk Has staHon a No Now when CH2C2 5 used as 60 Ivent fotady 60lvent as Follow Acuton e tH2 Az 7 Hexane (NON POlar when CH2U 15 Used and 0.810 A=0.742, Rf Value e Bo th that lompound 15 Polar in Natu and Hg means Hhiry Jor lolvent 15 used When Auone ve lolar bolvent and Hhan u2u RfB-086 RFA= 0613 and means yout tompound tontain which a q exhemley foasy Aluohal etc and tan 1 Ketone Hexane 1s uSed When (onirming Thar Has No naut on with Hexane whiuh REA 0.4 and Rp 0-334 Quie low solutt ie tompound NoN lolar and 5alut is Polar Natuu

RESULT o CONCLUsiONS Value 6 u9gesting in (Autone ond as wl as righ DrenDm ethone) that Compound is d exhrmley a Narure toly igh Gou Not ntatt with Hexane (NON-Polau) as ongfining b nta with Autone thar 4 Muiry A amd B au