. th ith days plaged 1st, 2nd, Let a; be the number of james he on tricty increesing seyrenu So, a,a2,.ツ974 is a Also we have KEIN sicy increading sequene is aso a tt ... 十kく153 a,tk, azth, Nw or and 212 Also, for kt2, 7, .. (5 humbers of the each +k 7 atk, atk, | and 153. between integer is an Pigen Hole- Primabu, at least two dthem must be the same . Hene by Now, atkjat and stridy incensing both are Sewen e So the two numbers which are to the same sequenuS em cannot same O ohe two seqpenes a,a,...,o2 and ark,atk/ Thns braom 6rom aa2-A and atk,9k,ッ9ュtk are same. one one So, a.atk r Sorma he has played k gamas, tor keg days ,, Henu or
Now ib k22then 159く4く……くaaく132 and 2359,+22<a+22く…くのみ+22く154 154 integes between I 154 9,+22,の422, . .ッ 9t22 a Also have We Claim: At least two othese 54 integers Same are Sail not, then +22 integers in some aYdex ie, these 51 integers are the values a,A Now we wil ind that order, ie, -the a 22,at22 22 a2a22 3
Clealy 23(5a,ez2) is also asigned in O. a is Tu smallıst of O So a,. A+ the same ime ). So a,a2, a,3, ../422-22 23 Carnet be Alsa 2,3,- .,22 cannst be in in 246a,p22),25-422)) Agan at the same time ,44(sa,t22). >», 23,24,.11 cannet he in 67(42722) is ako asignein- be in 45.Again Now, 45 has to at the same time 23 66.Again (2. Now 8 has to be Again 46,47,. . ., 66 camnat be in time 68a222),,5t22), ...,8eat2).So ,6,,83 camot be in in .So 5-89.Agoin S. a246, 4,, at the same O. Again Weau22) is also assagned Again . So, 133 is in a The some ime ax t same ime So, 160,41 Cannot be in . 1... 2za22) 3(42e),.-, 132(a22) Then 133 cannor be in and a133 ,which is a Controdiction as 2EIstto7v>'v
2 2 93 3 5= 5 a212 A1010 a13- 13 a1119 914- 19 18 2020 1515 2 21 28 50 a2618 a2547 a2116 235 a22-22 35=57 a56 3355 3153 a30 52 51 64 AI -63 42 94062 い38 - 60 a36-58 19 = 6y の49 =93 a4392 944-66 a43 65 16 5100 a55-99 aSA98 952-96 a53-97 a5195 a50-94 a101 a62-106 103 58-102 ち子- 101 64 lo8 133 のも -tev
edaim Ps corect. Henu our Some Thns 22 gamas he blayed cxactty And days ,2,i