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whats wrong i alwwys get like a 4.16 but never is correct can you solve this...
part 1 is wrong Calculate the pH of each solution. A solution containing 0.0243 M maleic...
part 1 is wrong
Calculate the pH of each solution. A solution containing 0.0243 M maleic acid and 0.034 M disodium maleate. The K, values for maleic acid are 1.20 x 10-?(K) and 5.37 x 10 (K2). pH = 2.00 A solution containing 0.0360 M succinic acid and 0.023 M potassium hydrogen succinate. The K, values for succinic acid are 6.21 x 10" (K1) and 2.31 x 10 "(K), pH = 4.01
Calculate the pH of each solution. A solution containing 0.0320 M maleic acid and 0.046 M...
Calculate the pH of each solution. A solution containing 0.0320 M maleic acid and 0.046 M disodium maleate. The Ka values for maleic acid are 1.20 x 10 (Ka1) and 5.37 x 10-7 (Ka2) 1.8 pH A solution containing 0.0306 M succinic acid and 0.019 M potassium hydrogen succinate. The Ka values for succinic acid are 6.21 x 105 (Kal) and 2.31 x 10 (Ka2) pH
O Attempt 7 Calculate the pH of each solution. A solution containing 0.0243 M maleic acid...
O Attempt 7 Calculate the pH of each solution. A solution containing 0.0243 M maleic acid and 0.034 M disodium maleate. The K, values for maleic acid are 1.20 x 10 (Kal) and 5.37 x 10 (Ka2) pH| 1.93 A solution containing 0.0360M succinic acid and 0.023 M potassium hydrogen succinate. The K, values for succinic acid are 6.21 x 10 (Kal) and 2.31 x 10 (K2) 9- = Hd 10
Calculate the pH of each solution. A solution containing 0.0345 M0.0345 M maleic acid and 0.047...
Calculate the pH of each solution. A solution containing 0.0345 M0.0345 M maleic acid and 0.047 M0.047 M disodium maleate. The ?aKa values for maleic acid are 1.20×10−2 (?a1)1.20×10−2 (Ka1) and 5.37×10−7 (?a2).5.37×10−7 (Ka2). pH= A solution containing 0.0320 M0.0320 M succinic acid and 0.018 M0.018 M potassium hydrogen succinate. The ?aKa values for succinic acid are 6.21×10−5 (?a1)6.21×10−5 (Ka1) and 2.31×10−6 (?a2).2.31×10−6 (Ka2). pH=
Please help me with this question. Thank you Calculate the pH of each solution. A solution...
Please help me with this question.
Thank you
Calculate the pH of each solution. A solution containing 0.0333 M maleic acid and 0.047 M disodium maleate. The K, values for maleic acid are 1.20 x 10-2 (K1) and 5.37 x 10-(K2). pH = 5.88 A solution containing 0.0264 M succinic acid and 0.016 M potassium hydrogen succinate. The K, values for succinic acid are 6.21 x 10- (Kal) and 2.31 x 10- (K pH = 3.99
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CHNH,) with...
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CHNH,) with 0.110 M HCI. The K methylamine is 5.0 x 10 of pH = 5.83 5.83 is wrong Calculate the pH of each solution. A solution containing 0.0243 M maleic acid and 0.034 M disodium maleate. The 1.20 x 10-(Kx1) and 5.37 x 10' (K). values for maleic acid are pll 2.00 A solution containing 0.0300 M succinic acid and 0.023 M potassium hydrogen succinate....
1.20 x 10- and Ka - 5.37 x 10-Determine the pll of 0.259 M Maleic acid...
1.20 x 10- and Ka - 5.37 x 10-Determine the pll of 0.259 M Maleic acid (H.CH,0,) is a diri acid with K maleic acid ( HC,H,O,) solution. < Hint pH = Because Kal is much larger than Kas you can assume that very little of the intermediate species (HC, H, 0) will dissociate and that the diprotic acid acts like a monoprotie acid.
Please explain in steps 3.) Calculate the concentrations of all molecular and ionic species and the...
Please explain in steps
3.) Calculate the concentrations of all molecular and ionic species and the pH in aqueous solutions that have the following formal compositions: a) 0.05 M acetic acid + 0.1 M sodium acetate; b) 0.2 M boric acid + 0.05 M sodium borate (pK, of boric acid = 9.24); c) 0.5 M hydrochloric acid. Some representative K, and pK, values: Acid Oxalic acid H3PO4 Formic acid Succinic acid Oxalate Acetic acid Succinate H2CO3 H2PO4 NH4+ HCO3 Piperidine...
Hi can someone show me how to solve these Cinnamic acid is obtained from oil of...
Hi can someone show me how to solve these
Cinnamic acid is obtained from oil of cinnamon. 125 millimoles of HCI were added to a solution containing 0.2 moles of a cinnamic acid and 0.3 moles of its conjugate base. After mixing, the pH of the solution was found to be 4.17. What is the pK, of cinnamic acid? A) 4.44 B) 4.17 C) 3.90 D) 4.93 E) 4.66 The digestive enzyme pepsin is secreted by stomach cells into an...
correct answer is highlighted in pink. how do i get the pH without it being 1.6?...
correct answer is highlighted in pink. how do i get
the pH without it being 1.6?
Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance H2CO3 Substance HCOH HNO2 НОСІ (COOH)2 Constant K = 1.8 x 10-4 Ka = 4.5 x 10-4 KA = 3.5 x 10-8 K = 7.2 x 10-4 KA = 4.0 x 10-10 Ki = very large K = 1.2 x 10-2 Ka=2.5 x 10-9 Constant Ki = 4.2 x...
part 1 is wrong
Calculate the pH of each solution. A solution containing 0.0243 M maleic acid and 0.034 M disodium maleate. The K, values for maleic acid are 1.20 x 10-?(K) and 5.37 x 10 (K2). pH = 2.00 A solution containing 0.0360 M succinic acid and 0.023 M potassium hydrogen succinate. The K, values for succinic acid are 6.21 x 10" (K1) and 2.31 x 10 "(K), pH = 4.01
Calculate the pH of each solution. A solution containing 0.0320 M maleic acid and 0.046 M disodium maleate. The Ka values for maleic acid are 1.20 x 10 (Ka1) and 5.37 x 10-7 (Ka2) 1.8 pH A solution containing 0.0306 M succinic acid and 0.019 M potassium hydrogen succinate. The Ka values for succinic acid are 6.21 x 105 (Kal) and 2.31 x 10 (Ka2) pH
O Attempt 7 Calculate the pH of each solution. A solution containing 0.0243 M maleic acid and 0.034 M disodium maleate. The K, values for maleic acid are 1.20 x 10 (Kal) and 5.37 x 10 (Ka2) pH| 1.93 A solution containing 0.0360M succinic acid and 0.023 M potassium hydrogen succinate. The K, values for succinic acid are 6.21 x 10 (Kal) and 2.31 x 10 (K2) 9- = Hd 10
Please help me with this question.
Thank you
Calculate the pH of each solution. A solution containing 0.0333 M maleic acid and 0.047 M disodium maleate. The K, values for maleic acid are 1.20 x 10-2 (K1) and 5.37 x 10-(K2). pH = 5.88 A solution containing 0.0264 M succinic acid and 0.016 M potassium hydrogen succinate. The K, values for succinic acid are 6.21 x 10- (Kal) and 2.31 x 10- (K pH = 3.99
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CHNH,) with 0.110 M HCI. The K methylamine is 5.0 x 10 of pH = 5.83 5.83 is wrong Calculate the pH of each solution. A solution containing 0.0243 M maleic acid and 0.034 M disodium maleate. The 1.20 x 10-(Kx1) and 5.37 x 10' (K). values for maleic acid are pll 2.00 A solution containing 0.0300 M succinic acid and 0.023 M potassium hydrogen succinate....
1.20 x 10- and Ka - 5.37 x 10-Determine the pll of 0.259 M Maleic acid (H.CH,0,) is a diri acid with K maleic acid ( HC,H,O,) solution. < Hint pH = Because Kal is much larger than Kas you can assume that very little of the intermediate species (HC, H, 0) will dissociate and that the diprotic acid acts like a monoprotie acid.
Please explain in steps
3.) Calculate the concentrations of all molecular and ionic species and the pH in aqueous solutions that have the following formal compositions: a) 0.05 M acetic acid + 0.1 M sodium acetate; b) 0.2 M boric acid + 0.05 M sodium borate (pK, of boric acid = 9.24); c) 0.5 M hydrochloric acid. Some representative K, and pK, values: Acid Oxalic acid H3PO4 Formic acid Succinic acid Oxalate Acetic acid Succinate H2CO3 H2PO4 NH4+ HCO3 Piperidine...
Hi can someone show me how to solve these
Cinnamic acid is obtained from oil of cinnamon. 125 millimoles of HCI were added to a solution containing 0.2 moles of a cinnamic acid and 0.3 moles of its conjugate base. After mixing, the pH of the solution was found to be 4.17. What is the pK, of cinnamic acid? A) 4.44 B) 4.17 C) 3.90 D) 4.93 E) 4.66 The digestive enzyme pepsin is secreted by stomach cells into an...
correct answer is highlighted in pink. how do i get
the pH without it being 1.6?
Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance H2CO3 Substance HCOH HNO2 НОСІ (COOH)2 Constant K = 1.8 x 10-4 Ka = 4.5 x 10-4 KA = 3.5 x 10-8 K = 7.2 x 10-4 KA = 4.0 x 10-10 Ki = very large K = 1.2 x 10-2 Ka=2.5 x 10-9 Constant Ki = 4.2 x...
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