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Question 10 0.5 pts What mass of lead sulfate (PbSO4) is formed in a lead-acid storage battery when 1.00 g of Pb undergoes ox

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Answer #1


Molar mass of Pb = 207.2 g/mol

mass of Pb = 1 g
mol of Pb = (mass)/(molar mass)
= 1/2.072*10^2
= 4.826*10^-3 mol



According to balanced equation
mol of PbSO4 formed = (2/1)* moles of Pb
= (2/1)*4.826*10^-3
= 9.653*10^-3 mol


Molar mass of PbSO4,
MM = 1*MM(Pb) + 1*MM(S) + 4*MM(O)
= 1*207.2 + 1*32.07 + 4*16.0
= 303.27 g/mol


mass of PbSO4 = number of mol * molar mass
= 9.653*10^-3*3.033*10^2
= 2.927 g
Answer: 2.927 g

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