Question

A 130 g block attached to a spring with spring constant 3.0 N/moscillates horizontally on a frictionless table. Its velocity is 20 cm/s when x0 = -5.8 cm .

What is the amplitude of oscillation?

Express your answer to two significant figures and include the appropriate units.

What is the block's maximum acceleration?

Express your answer to two significant figures and include the appropriate units.

What is the block's position when the acceleration is maximum?

Express your answer to two significant figures and include the appropriate units.

What is the speed of the block when x1 = 2.7 cm ?

Express your answer to two significant figures and include the appropriate units.

Answer 1

R = 2N/m m=130 D 0.1510— Amplitude ü the maximum stretch of the spring Let the amplitude be la At A only potential energy wiк ыр 25щі . Е. - КА“ . м п-5-8 м 2 - 2 xo -- м. : total energy a Ед: 17° +мо - = 20 хиля - 20 x 102 3. Е – Е, (фи ѕеrvлно и елору ә) 2. ет ұл - о“ - Ски“ p4 , ey* + * * > Зх. (58xio) 4 o-12 x(2 охо") 4- - (б. (015 - 25 A = -06 45 м. . - 6. Чри — меу і щи и аtCelica 4 оч „ А з Е на : 4.9 л. 4/5 Таллин (187x1024x: 1:4477 ) Scanned with CamScanner

Се ( Sч ч n= A sin wl.. a = d?n . a=-Aw² Sin wt. for a max , sinut = 1 - so, when sin wt="1. . NA: S6 ј! Н има уг шим роя Но, that is at ful amplitude bosition at will, on atto be - the position where acceleration üs maximum. ---- HEA sin wt. 2:7 = 6.us sin wt, sin wt, a 2.2 6.us ot, = sin / 2 7 ) 6:45 t = 5.155 at dni. Aw cos wt, - at 13515 o Aw cos wt. CS Scanned with 0-0645X4.9 cos (4.87 siis CamScanner , 0.281 ms