Calculate the amount of heat (in kJ) required to heat 1.01 kg of water from 0.05 0C to 35.81 0C. (Cs = 4.18 J/g 0C for water)
Given:
m = 1010 g
C = 4.18 J/g.oC
Ti = 0.05 oC
Tf = 35.81 oC
use:
Q = m*C*(Tf-Ti)
Q = 1010.0*4.18*(35.81-0.05)
Q = 1.51*10^5 J
= 151 KJ
Answer: 151 KJ
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