Use the following data to determine the molar heat of vaporization of chlorine.
T (C) -84.5 -71.2 -47.3
P (mmHg) 40.0 100.00 400.0
a. 34,700J
b. 21,900J
c. 9,99KJ
d. 712J
e. 317J
Ans b) 21990 J
p1 and p2 are pressures and T1 and T2 are temperatures in kelvin
ln (p1/p2) = (Delta H vap/ R) (1/T2 - 1/T1)
ln (400/100) = (Delta H vap / R) (1/201.8 - 1/225.7)
Delta H Vap = 21,990 J
Use the following data to determine the molar heat of vaporization of chlorine. T (C) -84.5...
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> how did you get 21,990? i only got 6,047
nayeon im Thu, Nov 11, 2021 12:01 AM