Question

The following information is given for cadmium at latm: To = 765.00°C T. 321.00°C Specific heat solid 0-2300 2 °C Specific heat liquid = 0.2640J/g °C AH (765.00°C) = 889.6 g AH(321.00°C) = 54.40 Jg A 26.40 g sample of liquid cadmium at 389.00°C is poured into a mold and allowed to cool to 21.00°C. How many l of energy are released in this process? (Report the answer as a positive number.) Energy = kJ The following information is given for water at 1 atm: T) = 100.00°C T. 0.00°C Specific heat solid = 2.100 g"C Specific heat liquid = 4.1843°C AHp (100.00°C) -2.259 x 10 Jig AH(0.00°C) = 333.5 g A 48.40 g sample of solid water is initially at -26.00'C. If 1.503 x 10 J of heat are added to the sample at constant pressure (P = 1 atm), which of the following is are true? (Select all that apply.) The sample is at a temperature of 0.00°C. The sample is a liquid The sample is a solid The sample is at a temperature greater than 0.00°C. The sample is a solid in equilibrium with liquid.

Answer 1

Mass सप २6. ५० T= उफ. Tf = 20.0°C Gad, - ०.२640TH °C Gds = ०.२30 19. °c AHavs = 54. ५० | Ed(309c, d) - Ed (3R1c, e) I = med x Crd, d x OT = 26.40 x 0.2640x (उर। - 389) - -4-39325 ca (उर। ८. Q) ____> च ( उर। ८, 5 ) १२ - - 41105 x mcd Post PPN--54. ५0 x 26. ५० 47 पर = - 1436.16 7 ( 3 , 5) ___- (२), 5) azu med x Eca, 5 x OT - Tot २७.५० x 0.2300 x (२) - 321) = -1फ 216 +cut 2 -4 3932 - 1436।।6-1621.6 --3-।।59 J 3 = 3 -3 रन

Amount of water - 4o.log Ti = -२6.0c Total treat (2)- 15030T 43. ५० (-२६c, 5) पप ५० (o.c, 5) GIF mw & Tuis & OT = ५०.५० x २00 x (0- (-26)) = २७५२.७५ ५८.५ ( 5) ८२ प ठ . ५० (०, ७) ERF mo & Hyus = पप्ठ ५० x 333.57 = 1614) ५ Total treat seg to convert sample (-25 t, 5) Sanple ( ८, 9) 4 = । नेप2 - २७५२.७५ + 1544 ___17 34.047 since I given & area. to sample is at 0.0000 The sample is solid at ea. with liquid. Dish T V पर गे