Determine the radius of an Al atom (in pm) if the density of aluminum is 2.71 g/cm3. Aluminum crystallizes in a face centered cubic structure.
Let’s do it steps-
2..Volume of unit cell:
1.792 x 10^-22 grams/unit cell x 1 cm^3/2.71 g = 0.6613 x 10^-22 =
6.613 x 10^-23 cm^3
3..Edge length = (6.613 x 10^-23)^1/3 = 4.05 x
10^-8 cm
The face diagonal of a unit cell
(Length edge)^2 + (length edge)^2 = (face diagonal)^2
(4.05 x 10^-8)^2 + (4.05 x 10^-8)^2 = (face diagonal)^2
face diagonal = 5.73 x 10^-8 cm
The face diagonal contains 4 radii.
4..Radius of Al atom = 1.43 x 10^-8
1.43 x 10^-8 cm x 10^12 picometers/meter x 1 meter/100 cm =
143 pm
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Determine the radius of an Al atom (in pm) if the density of aluminum is 2.71...
Determine the radius of in Al atom (in pm) if the density of the aluminum is 2.71g/cm3. Aluminum crystallizes in a face centered cubic structure with an edge length of 2 square root 2 r
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