Question

1) **The electron configurations of five different elements are shown below. Which of these elements is expected to have the largest second ionization energy (IE2)?** (a) 1s 2s 2p 3s1 (b) 152 2s22p6352 (c) 152 282 2p 3s 3p1 (d) 152 252 2p6 352 3p4 (e) 1s 2s 2p 3s 3p5 2) **A single Lewis Structure of the formate ion (HCO2) is shown below. Which statement best describes the bonding character of this ion?** H-C-0: 10: (a) One double bond and two single bonds (b) One double bond and two delocalized single bonds (c) Three equivalent 1, bonds (d) One single bond and two equivalent 1 bonds (e) 007 James Bonds 3) **Which of the following species has a T-shaped molecular geometry (MG)?** (a) ICI: (b) NH3 (e) 03 (d) SO2

Answer 1

the (1) The element which is expected to have largest second ionization emergy (Df2 — o is? 252 2p63s? 3p!. . ( 152 282 2pbgs' res ase 252286 1&2, *2pS e son alg. De estable electronic - configuration) D is die (completely filled electronics Configuration) (1) ise es? ppódem in 252 ppt get med © 192 25² 26 352 3p' TET! ce is22s22p6352 The IS Istable electronic a e configuration (completely felles electronic configuration) a ist 252 2p6 35? 3p 4 ray 152 23° 2page apa - 1?2s%2pkns sp de DeiHald filled electronic 2 configuration) (stable electronic configuration) @ 1522 52-2p6352 905 me 1522322p62523p“ 15%28 3p3 (stable electronic 2 configuration

Donisalim energy of an atom e's defined as Menium amount of energy requvied to remove the most loosely bound electron, the valence electron, of an isolated neutral gasesues atom In case of (b) and (e), after removing two eos from the valence orbital we get stable electronic configuration. To get stable electronic configuration , loosing of and electron becomes easier and it gets minimum amount of energy. So, 1E2 ( second ionisation emergy is lowest for (by and le). . , But for (a), (c), (d) after loosing one electron from valence orbital we get stable electronic conlauration. Sog removal of and electron from beans atom becomes hardest. So, PhD of (a), (6 4 (d) are greater than that of 24€ Againy, in.ca But in case of (a) and (d) , removal of and election from p-on bital becomes more easier than a where removing of eos happens from s-orbital. As, s ombit al mos is more closer to the nucleus , effective nuclear charge is greater in case of co. This is why, if of co to largest value. than those of others. ܘܬܐ B has the