I need this answered and explained!
Co2 is having highest reduction potential and H2 being electron donor having lowest reduction potential in redox couple so maximum difference is there between two molecules . Product formed after reduction will be acetate like NAD gets reduced to NADH . Energy released in ETC is due to electron losing energy when being transfered to more electronegative molecule having more reduction potential .
I need this answered and explained! Redox couple Eo (V) CO2/glucose (-0.43) 24 e 2H /H2...
I ain't certain about how to solve this question I might be over thinking it, but it has been bothering me a lot. I think the answer would E=-0.30 but I ain't certain. Eo' (V) -0.50 -0.40 -0.30 -0.20 -0.10 Redox couple con/glucose (-0.43) 24 e 2H+ /Hz (-0.42) 2 e CO2/methanol (-0.38) 6 e NAD+/NADH (-0.32) 2 e co/acetate (-0.28) 8 e S/H,5 (-0.28) 2 e 5042/H25 (-0.22) 8 e Pyruvate/lactate (-0.19) 2 e 5,062-15, 0,2-(+0.024) 2 e Fumarate/succinate...
E Volts) 6 co2/glucose 0.43] -0.5 I-0.42] -0.4 NAD /NADH 0.32] -03 -0.2 -0.1 Fumarate/succinate 0.03] 0.0 [0.10] +0.1 2 H /H2 I- 0.27] FADIFADH2 0.18] S°/H2S CoQ/CoQH2 +0.2 Cyt C (Fe )Cyt C (Fe+) [0.25] +0.3- +0.4 +0.5 +0.6 No,INO2 [0.421 Fe3+/Fe2+ 4 0,H20 (0.82108 10.77) +07
ALEKS data table may not include the value, if not please just include the E value and I will go through the table and leave the answer in the comments A certain half-reaction has a standard reduction potential Ered- provide at least 0.50 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell 0.53 V. An engineer proposes using this half-reaction...