Alkane halogenation

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Alkane halogenation

Alkane halogenation is a two-step reaction, as shown below. Using the table of bond dissociation energies, calculate the enthalpy of each step and the enthalpy ofthe overall reaction.

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Answer 1

Answer #1

34 -101 -65

answered by: Learner

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Answer 2

Answer #2

34, -99, -65

answered by: 400

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Answer 3

Answer #3

wrong

answered by: Teresa Joseph

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Answer 4

Answer #4

the answer is -9 -111 -120

answered by: janeile

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Answer 5

Answer #5

don't listen to those quack answers - this is very simple - answers are (-18) , (-112), (-130). You have wrong numbers in the blanks my friend.

answered by: sajid

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Answer 6

Answer #6

Step 1 = 34 kJ/mol
Step 2 = -99 kJ/mol
Overall = -65 kJ/mol

answered by: Lakia

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Answer 7

Answer #7

34, -99, -65. you must: (bonds Broken "~H")+(Bonds Formed "~H"). Bonds broken have positive values of H while the bonds formed have negative values of H

answered by: max

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Answer 8

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Alkane halogenation

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