Question

Airline passengers arrive randomly and independetly at the passenger screening facility at a major international airport....

Airline passengers arrive randomly and independetly at the passenger screening facility at a major international airport. the mean arrival rate is 10 passengers per minute. compute the probability of no arrivals in a 15 second period.
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Answer #1
Mean in 15 sec period is 10/4= 2.5.
So using the Poisson distribution the probability of no arrivals is e^(-2.5)= 0.08208
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