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2. If 5.45 grams of metallic copper was reacted with 20.0 mL of concentrated (16.0 M) nitric acid, how many grams of Cu(NO3)2
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Answer #1

Equation 3Cu +8HNO3 3Cu (NO32NO 4H2O 1 mol Cu 3 mol Cu (NO Amount of Cu (NO), formed from Cu 5.45 g x- X = 63.55 g 3 mol Cu 1

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