Question

this was the only information I was given. There is no data.

question one data

question three data

Queeton H Refer to the accompanying data set and use the 30 sorew lengh to consruct a brequency d uon Beginwh a lower s 11/2 n Does the frequeney distribution appear to be consisent wth the lbe? Why or why nol wre lbeled of 1.470 in, and uecess widh of010 The so heving engh of m Cck on icon to view the dat Complete he frequency distribution below Langth (n) Frequency 1470 munded to the oea Tee in Canstat the ounlae freauency dstributon for the gven dae Age tyears) of Best Actress when award was wond 20-29 30-39 Age years) of Bet Actress when awad was wae Cumuate Fency Frequency Less than 30 Less hen 40 Less than 0t s0.59 Less han 60 70-796 Lese than Lese than 90 and use a ciess width of 02 voll Does he eu requency distribuon with ve dasses Begin with a iower class imt of 127 8 vols Reler to the socompanying dala sel and use the 25 home vollege appear to have a normal distribution? Why or why no? measurements to consinuct Cliek the icon to view the dala Complete the frequency distribution below. Frequency Voltage (volts) The data represents the daly rainfall (in inches) for one month. Construct a frequency distribution beginning with a lower class imit o 35 of 0.00 and use a class width of 0.20. Does the frequency distribution appear to be roughly a nomal distribuon? 029 0 0.18 121 0.12 a.02 022 0.06 0.56 0.02 02 0 021 021 Daily Rainfall in inches) 080-0 99 1.00-1.19 Daily Rainfal in inches) Frequency Frequency 0.00-0.19 0.20-039 1.20-1.390 040-0 590 0.60-079 3.. .l.5 3... Data Table Screw Lengths (inches) 1.492 1.503 1.505 1.506 1.484 1.498 1.502 1.475 1.501 1.508 1.491 1.494 1.486 1.497 1.509 1.507 1.488 1.491 1.499 1.496 1.512 1.508 1.505 1.479 1.489 1.505 1.513 1.501 1.491 1.502 Print Done More Info Voltage Measurements From a Home Home Home Home Full Home (volts) Day (volts) Day (volts) Day (volts) data 15 16 Day 128.5 128.0 22 128.3 set 128.1 128.1 8 1 128.4 23 2 128.5 128.2 3 128.3 10 128.5 17 127.9 24 128.1 128.2 4 128.5 11 18 128.1 25 128.3 128.5 5 12 127.8 19 128.2 6 127.8 13 20 128.2 128.6 7 128.2 14 128.3 21 128.4 Print Done ver. Clear All MacBookA N2

Answer 1

Only question 1 has been solved. ( Distribution of length) ( The remaining questions the numbers are not clearly possible. Please post bigger and clear pictures.)

1. Arrange the data in ascending order as shown below.

A 1 Length 2 1.475 3 1.479 4 1.484 5 1.486 6 1.488 7 1.489 1.491 9 1.491 10 1.491 1.492 11 12 1.494 1.496 13 14 1.497 15 1.498 1.499 16 17 1.501 18 1.501 19 1.502 20 1.502 21 1.503 st C

2. Given the information in the question construct an interval table as shown below with an increment of 0.01

3. Count the number of the length in each interval and write the count as frequency.

The final frequency distribution is given below.

Lower limit Upper Limit Frequency 1.47 1.48 2 1.49 1.48 4 1.49 1.5 9 1.5 1.51 13 1.52 1.51 2