Question

Problem Solving:(Show all work in every problem) (10 points) The figure shows the bonding of cytosine and guanine. The O-H and H-N distances are each 0.110 nm. In this case, assume that the bonding is due only to the forces along the O-H-O, N-H-N, and O-H-N combinations, and assume also that these three combinations are parallel to each other. (NOTE: Use k =9.00 x 10° Nm2/C) 1. Calculate the net force that cytosine exerts on guanine due to the preceding three combinations. Is this force attractive or repulsive? a. b. 0.290 nm Guanine (H) Cytosine 0.300 H H 0.290 nm

Answer 1

Answer (0) Net force that cytosine guanine Ccevts on from ithe figure condlude thet Can Here are (+ a0-H atiacton tords ) 1 N-H auttvactu toned repulhive tonds repabive uorel 4) 1 so that rom th ulombs daw F= K 1,92 Y2 Con idaratiu that Tare in to O.18 nm N-H

There fove 0-H attvactu: Co.4e) (o.2e) Fot = (0.18 X10-9)2 FoFon -10 J0 IA (i-8 A) D.08 k o2 FOH atractum: N-H O-190nm 1 H O-30 nm P2

(0.2e) (0.2e) NH 1.9 A )2 FNH O.08 ke2 O-N Repulsi on: x (0112) (0.2e) FoN (2.-70 A)2 0.08 Ke2 PoN 2.90 A)2 1Repulsion N-N K (0-2e) Co-2e) FNN (3-00A)2 P3

FIVN O.04 Ke2 (3.00A) 2 Fcoj=2FOH Frv FoN FN 0.08 O-O4 + o.08 O.04 U-8)R Kez X 10 (9.00 지09) (1-b0ax 10-9)년 (1X10-10m O-0 369 10 N 8.5a X 10 het fore excets Fl6 (b Sinte, it pashve value. The is ATTRACTIVE