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Part A In a physics laboratory experiment, a coil with 240 turns enclosing an area of 14.0 cm2 is rotated in a time interval

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Answer #1

Number of turns N = 240

Area of cross section of the coil A = 14 cm2 = 14\times10-4 m2

Earth's magnetic field B = 5.7\times10-5 T

Time interval t = 4.7\times10-2 s

A) Before the rotation , the magnetic field is perpendicular to the plane of the coil , angle between the magnetic field and normal to the plane of the coil \theta 1 = 0 degree

Magnetic flux \phi 1 = NBAcos\theta1

\phi1 = 240\times5.7\times10-5\times14\times10-4\timescos0

\phi1 = 19.15\times10-6 Wb

B) After rotation of the coil the plane of the coil is parallel to the earth's magnetic field , angle between the magnetic field and normal to the plane of the coil is 90 degree.

Magnetic flux \phi 2 = NBAcos90

\phi2 = 0 Wb

C) Average emf induced in the coil

E = - (\phi2 - \phi 1)/t

E = - ( 0 - 19.15\times10-6) / 4.7\times 10-2

E = 4.074 \times 10-4 V

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