Question

Stoichiometry A mixture of AgNO3 and LisPO, in water results in the formation of LINO3 and Ag3PO4. Write the balanced equation for this reaction, indicating the appropriate physical states of each of the four compounds in the reaction. What is the mass of AgNO3 in grams that is required to react completely with 35.0 g of Li3PO4?

Answer 1

1)

3 AgNO3(aq) + Li3PO4(aq) -> Ag3PO4(s) + 3 LiNO3(aq)

2)

Molar mass of Li3PO4,

MM = 3*MM(Li) + 1*MM(P) + 4*MM(O)

= 3*6.968 + 1*30.97 + 4*16.0

= 115.874 g/mol

mass of Li3PO4 = 35 g

mol of Li3PO4 = (mass)/(molar mass)

= 35/1.159*10^2

= 0.3021 mol

According to balanced equation

mol of AgNO3 required = (3/1)* moles of Li3PO4

= (3/1)*0.3021

= 0.9062 mol

Molar mass of AgNO3,

MM = 1*MM(Ag) + 1*MM(N) + 3*MM(O)

= 1*107.9 + 1*14.01 + 3*16.0

= 169.91 g/mol

mass of AgNO3 = number of mol * molar mass

= 0.9062*169.91

= 154 g

Answer: 154 g