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A student dissolves 12.1 g of potassium chloride (KCl) in 250. g of water in a well-insulated open cup. He then observes the

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Answer #1

1. endothermic because temperture drops

2. Heat released = mass of water * specific heat of water * temperature change = 250 * 4.184 * (21 - 17.1) = 4079.4 J = 4.08 KJ

3. Moles of KCl = mass / molar mass = 12.1 / 74.5 = 0.162 moles

Standard enthalpy of solution = Heat / moles = 4.08 / 0.162 = 25.19 KJ/mol

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