Question

Incorrect Your answer is incorrect • Row 2: Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations • Row 3: Your answer is wrong. In addition to checking your moth, check that you used the right data and DID NOT round any intermediate calculations. thermometer stimer A student runs two experiments with a constant volume "bomb" calorimeter containing 1500 g of water (see sketch at right). First, a 5.000 g tablet of benzoic acid (C,H,CO,H) is put into the "bomb" and burned completely in an excess of oxygen. (Benzoic acid is known to have a heat of combustio of 26.454 kJ/g.) The temperature of the water is observed to rise from 13.00 °C to 31.00 °C over a time of 13.5 minutes. Next, 5.880 g of ethanol (C,H,OH) are put into the "bomb" and similarly completely burned in an excess of oxygen. This time the temperature of the water rises from 13.00 °C to 36.37 °C. Use this information, and any other information you need from the ALEKS Data resource, to answer the questions below about this reaction: A "bomb calorimeter C,H,OH(I) + 30,(8) - 200,(g) + 3 H2O(g) Be sure any of your answers that are calculated from measured data are rounded to the correct number of significant digits. Note for advanced students: it's possible the student did not do these experiments sufficiently carefully, and the values you calculate may not exactly match published values for this reaction. Dexothermic Is this reaction exothermic, endothermie, or neither? endothermic X 5 2 neither If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in the second experiment. 148.5 kJ Calculate the reaction enthalpy AH per mole of CO, 659.4 kJ mol

Answer 1

Amt. Det benzoic acid = 5:00 G AH Comt = 26.454 RJE Total that seleased = 59 x 25.454 KIIG = 13:27 Aht of water = 1500 g twater - 4.184 Il 3 °C AT= 31-13 = 18°c heat absorted by water can = mxt XOT - = 1500g x 4.184 x 18°C = 112.968KJ total heat released = Italon tag ССЯ 132.27 = toad X OT + 112.968 Ccal = 132. 27 - 112.968 Iloc 18 = 1,07233 J1 °C Amount o ethanol = 5:8gog no a moles of ethanol = 518go mole 46.07 = o.l276318 hole as per reaction no. produced = xo. reaction, not moles of co - XO.R75318 mole = 0.25525 mole AT= 35.37 -13 = 23 37°C treat seletised by reaction = chomt xoT + c watey x mass XAT

= 1072.33 X 23:37 + 1500 x 4.184x23:37 = 25050.ZZZ2 + 145670.12 J = 171730.342 I a 1711 73 KJ Amount of the at released = 171.73 RJ 4 Hze | mole coz = 171.73_ KJ| mole 0.25525 = 672.765 kJ/mole Ans Reaction is exothermic A Hre (qreaction) = 171.73 KJ ohran= 572.765 KJ/mole of mote of coa too