31. + -10.1 points 0/4 Submissions Used Balance the following equations. (Use the lowest possible whole-number...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) NO3- (aq) + As2O3(s) = N2O3(aq) + H3ASO4(aq) N03* + As2O3 + H+ + O H20=O N203+ H3A504 + H+ + H20 (b) Clozaq) + As(s) Æ HClO(aq) + H3AsO3(aq) DC103+ As + OH+ + H2O=OHCO + H2A503 + H+ + OH20 (c) CIO-(aq) + Pb(OH)42-(aq) = Cl(aq) + PbO2(s) D clo + Pb(OH)42- + D OH + H2O=D C + PbO2 + OH +...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr202-(aq) + NO2 (aq) = Cr3+ (aq) + NO3"(aq) Cr20,2- + NO3 + H+ + H2O= Cr3+ + NO3 + H+ + H20 (b) Mn04 (aq) + CH3OH(aq) Æ Mn2+ (aq) + HCO2H(aq) MnO4 + CH3OH + H+ + H2O= Mn2+ + HCO2H + H+ + H2O (c) ClO2(aq) + H2O2(aq) = C102 (aq) + O2(9) C102 + H2O2 + OH + H20 = ClO2...
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) MnO4-(aq) + Cl-(aq) Mn2+(aq) + Cl2(aq) MnO4- + Cl- + H+ + H2O Mn2+ + Cl2 + H+ + H2O (b) Cr2O72-(aq) + NO2-(aq) Cr3+(aq) + NO3-(aq) Cr2O72- + NO2- + H+ + H2O Cr3+ + NO3- + H+ + H2O (c) Tl2O3(s) + NH2OH(aq) TlOH(s) + N2(g) Tl2O3 + NH2OH + OH- + H2O TlOH(s) + N2 + OH- + H2O (d) CrO42-(aq) + C2O42-(aq) Cr(OH)3(s) + CO2(g) CrO42- + C2O42- + OH- + H2O Cr(OH)3 + CO2 + OH- + H2O
Balance these chemical equations. (Use the lowest possible whole number coefficients.) (a) C4H10 + O2 → CO2 + H2O (b) Pb(NO3)2 → PbO + NO2 + O2 (c) N2H4 + O2 → H2O2 + N2 (d) NH3 + O2 → NO2 + H2O (e) NH3 + O2 → N2 + H2O (f) Fe(OH)2 + O2 + H2O → Fe(OH)3
Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) Balance the following equations. (Use the lowest possible whole-number coefficients. These may be zero.) (a) Cr2022(aq) + I (aq) = Cr3+ (aq) + 103 (aq) 1 Cr2O72- + 1 1 + 8 H+ + 1 X H20 = 2 Cr3+ + 1 103 + 1 X H+ + 4 H2O (b) CIO3-aq) + As(s) Æ HCIO(aq) + H3A5O3(aq) 3 CIO3 + 4 As + 3 H...
Part A What is the reduction half reaction for the following chemical reaction in a basic solution? Sn2+(aq) + 2 CIO, (aq) + OH(aq) + SnO(s) + 2 CIO2(aq) + H2O() Sn2(aq) + 4 OH(aq) - SnOz(s) + 2 H2O() +2e CIO(aq) + 2 H(aq) +- CIO3(aq) + H2O() CIO (aq) + H2O()+'+ CO2(aq) + 2 OH(aq) Sn2+ (aq) + 2 H20(1) - SnO2(s) + 4 H*(aq) + 2e* Submit Request Answer Part A What is the shorthand notation that...
Balance the following equations. (Use the lowest possible whole number coefficients. Include states-of (2) AIHz(8) + H2O(l) + Al(OH)3(8) + Hz(9) (6) Nb(NO3)(s) Nb2O3(s) + NO2(g) + 02 (9) (C) CH3NH2(g) + O2(g) + CO2(g) + H2O(l) + N2 (9) Submit Answer Try Another Version 10 item attempts remaining
at 298 K. (Use the For each of the following reactions, balance the chemical equation, calculate the emf, and calculate AG smallest possible coefficients for H2000), H(aq), and HO (aq). These may be zero.) (a) In basic solution CH(OH)3(s) is oxidized to cro.2(aq) by Cio (aq). Cr(OH)3(s) + Cio(aq) + OH" (aq) - 0 Cro? (aq) O r(aq) + H2O(!) (b) In acidic solution copper(t) lon is oxidized to copper(IT) Ion by nitrate ion. Cu(aq) + NO3(aq) + (aq) +...
balance each of the following equations Fall 209 CHM 105.004 Exam 2 Answer all the question in order in the blue book. Plesse leave at least two lines between question and show your calculations for full credit. N-6.023 x 10” particles per mol: R 0.08.205 L-atm/(mol-K) b) Al2(PO4) 3 e) CuSO4-5 H2O 1. Calculate the molar masses of: a) (NH4)2SO4 2. Calculate: a) the number of atoms of calcium in a 10.50 g sample of the metal b) the mass...
33 0.1 points 0/4 Submissions Used Using data found in Appendix E of your textbook caloulate the nonstandard emf for each of the following reactions if the concentration of each of the lons in these reactions is 0.0001 molar and everything else is standard (use 298K for the temperature, R 8.314 mol-K, and F 96,485 C/mol): My Notes (a) 1 Fala) + 1 Cus)->2 F (aq) +1 C(aq) E- (b) 2 Cu'(aq) 1 Fe(s)->2 Cu(s) + 1 Fe (a) E...